Pada bahan kali ini akan mengulas ihwal jumlah dan selisih dua sudut dalam trigonometri yaitu pada sinus, cosinus, dan tangen.
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02. Tentukanlah nilai dari:
(a) sin 15o
(b) sin 285o
jawaban
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03. Tentukanlah nilai dari:
(a) tan 105o
(b) tan 255o
Jawab
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04. Tentukanlah nilai dari :
(a) sec 255o
(b) cot 345o
Jawab
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05. Diketahui sin α = –4/5 dan cos β = 7/25, dimana α sudut di kwadran III dan β di kuadran IV. Tentukanlah nilai dari:
(a) sin (α + β )
(b) cos ( α – β )
(c) tan( α + β )
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06. Buktikanlah bahwa cos(A + B).cos(A – B) = cos2A – sin2B
Jawab
Ruas kiri = cos(A + B).cos(A – B)
= (cosA.cosB – sinA.sinB)( cosA.cosB + sinA.sinB)
= cos2A.cos2B – sin2A.sin2B
= cos2A.(1 – sin2B) – (1 – con2A).sin2B
= cos2A – cos2A.sin2B – sin2B + cos2A.sin2B
= cos2A – sin2B
= ruas kanan
Rumusnya yaitu sebagai diberikut:
01. Tentukanlah nilai dari:
(a) cos 75o
(b) cos 165o
Jawab
02. Tentukanlah nilai dari:
(a) sin 15o
(b) sin 285o
jawaban
03. Tentukanlah nilai dari:
(a) tan 105o
(b) tan 255o
Jawab
04. Tentukanlah nilai dari :
(a) sec 255o
(b) cot 345o
Jawab
05. Diketahui sin α = –4/5 dan cos β = 7/25, dimana α sudut di kwadran III dan β di kuadran IV. Tentukanlah nilai dari:
(a) sin (α + β )
(b) cos ( α – β )
(c) tan( α + β )
06. Buktikanlah bahwa cos(A + B).cos(A – B) = cos2A – sin2B
Jawab
Ruas kiri = cos(A + B).cos(A – B)
= (cosA.cosB – sinA.sinB)( cosA.cosB + sinA.sinB)
= cos2A.cos2B – sin2A.sin2B
= cos2A.(1 – sin2B) – (1 – con2A).sin2B
= cos2A – cos2A.sin2B – sin2B + cos2A.sin2B
= cos2A – sin2B
= ruas kanan
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